Magnetic measurements suggest that Cu exists in magnetic +2 oxidation state in V10O28-CuCl-phen and non-magnetic +1 oxidation state in V10O28-CuO-phen. Copper(I) chloride, commonly called cuprous chloride, is the lower chloride of copper, with the formula CuCl.The substance is a white solid sparingly soluble in water, but very soluble in concentrated hydrochloric acid.Impure samples appear green due to the presence of copper(II) chloride (CuCl 2). In CuCl, Cl is -1 and Cu is +1. The relative stabilities of each oxidation state depend on the nature of ligands and anions as well as the nature of the solvent medium. Regards. Forming copper(I) complexes (other than the one with water as a ligand) also stabilizes the copper(I) oxidation state. Which it adopts is compound-specific or may be affected by conditions like temperature, pH, etc. You have also seen blue-green Cu+2 ion, representing the copper (+2) oxidation state. See the answer. Copper(II) chloride, also known as cupric chloride, is a chemical compound.Its chemical formula is CuCl 2.It contains copper in its +2 oxidation state.It also contains chloride ions. Question: 3. What Is The Oxidation State Of The Copper In The Compound CuCl2? This problem has been solved! Assume we add an excess of copper metal and allow the reduction of Cu 2+ to proceed, via Cu + Cu 2+--> 2 Cu + and that most of the Cu + precipitates out of the solution as CuCl (s). In this IL, copper in +1 oxidation state was stabilized as the chlorocuprate(I) anions CuCl 2 −, Cu 2 Cl 3 −, and Cu 3 Cl 4 − . What Is The Oxidation State Of The Copper In The Compound CuCl2? Previous question Next question Transcribed Image Text from this Question. Metallic copper is the other product which has zero valency. Expert Answer . The Natural Bonding Orbital analysis confirms the formation of covalent σ‐Cu–C bond in these complexes. In this lab, we will reduce the Cu+2 ion to the colorless Cu+ ion by reaction Assume y mol of copper metal reacted away, this would yield 2y mol of CuCl, reducing the amount of chlorine in the solution by 2y mol, leaving 2x - 2y. 3. Therefore some part of Cu in CuCl is reduced from +1 to 0 and some part Cu in CuCl is oxidized from +1 to +2 The comparison of geometric and electronic structures of chloroorganocuprates and corresponding copper(II) chloride complexes with the same number of chlorine atoms indicates the higher Cu oxidation state in [CuCl n CH 3] 2−n. Explanation: Hello, In this case, for the compound CuCl, the oxidation states are shown below: As there are only one copper and one chlorine, therefore, the name of such copper ion is copper (I) ion as the roman number, I, represent its oxidation state which is +1.. 2 CuCl (s) + 2 Na 2 SO 4(aq) + 2 HCl (aq) + C 6 H 6 O 6(aq) Introduction: In previous labs, you have seen orangish-brown colored Cu metal, an example of the copper (0) oxidation state. In the experiment below the copper(I) ions once formed, react with chloride ions to form the insoluble copper(I) chloride. Answer: Copper (I) ion. This IL was shown to be stable against moisture and air oxidation, since the copper(I)-containing sorbents used for desulfurization are often sensitive to external factors. The oxidation state can vary from any among the values -2, +1, +2, +3 or +4. In CuCl2 Cl is -1 and Cu is +2. Show transcribed image text. This is also redox reaction in which the same substance (Cu) is both oxidized and reduced.